The Mixed Precision Iterative Refinement (MPIR) solver example..
This example depends on iterative-refinement.
This example manually implements a Mixed Precision Iterative Refinement (MPIR) solver.
In this example, we first read in a matrix from file, then generate a right-hand side and an initial guess. An inaccurate CG solver in single precision is used as the inner solver to an iterative refinement (IR) in double precision method which solves a linear system.
The commented program
RealSolverType inner_reduction_factor{1e-2};
Print version information
Figure out where to run the code
if (argc == 2 && (std::string(argv[1]) == "--help")) {
std::cerr << "Usage: " << argv[0] << " [executor]" << std::endl;
std::exit(-1);
}
const auto executor_string = argc >= 2 ? argv[1] : "reference";
std::map<std::string, std::function<std::shared_ptr<gko::Executor>()>>
exec_map{
{"cuda",
[] {
}},
{"hip",
[] {
}},
{"dpcpp",
[] {
0, gko::ReferenceExecutor::create());
}},
{"reference", [] { return gko::ReferenceExecutor::create(); }}};
executor where Ginkgo will perform the computation
const auto exec = exec_map.at(executor_string)();
Read data
auto A =
share(gko::read<mtx>(std::ifstream(
"data/A.mtx"), exec));
Create RHS and initial guess as 1
auto host_x = vec::create(exec->get_master(),
gko::dim<2>(size, 1));
for (auto i = 0; i < size; i++) {
host_x->at(i, 0) = 1.;
}
Calculate initial residual by overwriting b
auto one = gko::initialize<vec>({1.0}, exec);
auto neg_one = gko::initialize<vec>({-1.0}, exec);
auto initres_vec = gko::initialize<real_vec>({0.0}, exec);
A->apply(one, x, neg_one, b);
b->compute_norm2(initres_vec);
Build lower-precision system matrix and residual
auto solver_A = solver_mtx::create(exec);
auto inner_residual = solver_vec::create(exec);
auto outer_residual = vec::create(exec);
A->convert_to(solver_A);
b->convert_to(outer_residual);
restore b
Create inner solver
auto inner_solver =
cg::build()
.with_criteria(
.with_reduction_factor(inner_reduction_factor),
gko::stop::Iteration::build().with_max_iters(max_inner_iters))
.on(exec)
->generate(
give(solver_A));
Solve system
exec->synchronize();
std::chrono::nanoseconds time(0);
auto res_vec = gko::initialize<real_vec>({0.0}, exec);
auto initres = exec->copy_val_to_host(initres_vec->get_const_values());
auto inner_solution = solver_vec::create(exec);
auto outer_delta = vec::create(exec);
auto tic = std::chrono::steady_clock::now();
int iter = -1;
while (true) {
++iter;
convert residual to inner precision
outer_residual->convert_to(inner_residual);
outer_residual->compute_norm2(res_vec);
auto res = exec->copy_val_to_host(res_vec->get_const_values());
break if we exceed the number of iterations or have converged
if (iter > max_outer_iters || res / initres < outer_reduction_factor) {
break;
}
Use the inner solver to solve A * inner_solution = inner_residual with residual as initial guess.
inner_solution->copy_from(inner_residual);
inner_solver->apply(inner_residual, inner_solution);
convert inner solution to outer precision
inner_solution->convert_to(outer_delta);
x = x + inner_solution
x->add_scaled(one, outer_delta);
residual = b - A * x
outer_residual->copy_from(b);
A->apply(neg_one, x, one, outer_residual);
}
auto toc = std::chrono::steady_clock::now();
time += std::chrono::duration_cast<std::chrono::nanoseconds>(toc - tic);
Calculate residual
A->apply(one, x, neg_one, b);
b->compute_norm2(res_vec);
std::cout << "Initial residual norm sqrt(r^T r):\n";
write(std::cout, initres_vec);
std::cout << "Final residual norm sqrt(r^T r):\n";
write(std::cout, res_vec);
Print solver statistics
std::cout << "MPIR iteration count: " << iter << std::endl;
std::cout << "MPIR execution time [ms]: "
<< static_cast<double>(time.count()) / 1000000.0 << std::endl;
}
Results
This is the expected output:
Initial residual norm sqrt(r^T r):
1 1
194.679
Final residual norm sqrt(r^T r):
1 1
1.22728e-10
MPIR iteration count: 25
MPIR execution time [ms]: 0.846559
Comments about programming and debugging
The plain program
#include <ginkgo/ginkgo.hpp>
#include <fstream>
#include <iomanip>
#include <iostream>
#include <map>
#include <string>
int main(int argc, char* argv[])
{
using ValueType = double;
using SolverType = float;
using IndexType = int;
RealValueType outer_reduction_factor{1e-12};
RealSolverType inner_reduction_factor{1e-2};
if (argc == 2 && (std::string(argv[1]) == "--help")) {
std::cerr << "Usage: " << argv[0] << " [executor]" << std::endl;
std::exit(-1);
}
const auto executor_string = argc >= 2 ? argv[1] : "reference";
std::map<std::string, std::function<std::shared_ptr<gko::Executor>()>>
exec_map{
{"cuda",
[] {
}},
{"hip",
[] {
}},
{"dpcpp",
[] {
0, gko::ReferenceExecutor::create());
}},
{"reference", [] { return gko::ReferenceExecutor::create(); }}};
const auto exec = exec_map.at(executor_string)();
auto A =
share(gko::read<mtx>(std::ifstream(
"data/A.mtx"), exec));
auto host_x = vec::create(exec->get_master(),
gko::dim<2>(size, 1));
for (auto i = 0; i < size; i++) {
host_x->at(i, 0) = 1.;
}
auto one = gko::initialize<vec>({1.0}, exec);
auto neg_one = gko::initialize<vec>({-1.0}, exec);
auto initres_vec = gko::initialize<real_vec>({0.0}, exec);
A->apply(one, x, neg_one, b);
b->compute_norm2(initres_vec);
auto solver_A = solver_mtx::create(exec);
auto inner_residual = solver_vec::create(exec);
auto outer_residual = vec::create(exec);
A->convert_to(solver_A);
b->convert_to(outer_residual);
b->copy_from(host_x);
auto inner_solver =
cg::build()
.with_criteria(
.with_reduction_factor(inner_reduction_factor),
gko::stop::Iteration::build().with_max_iters(max_inner_iters))
.on(exec)
->generate(
give(solver_A));
exec->synchronize();
std::chrono::nanoseconds time(0);
auto res_vec = gko::initialize<real_vec>({0.0}, exec);
auto initres = exec->copy_val_to_host(initres_vec->get_const_values());
auto inner_solution = solver_vec::create(exec);
auto outer_delta = vec::create(exec);
auto tic = std::chrono::steady_clock::now();
int iter = -1;
while (true) {
++iter;
outer_residual->convert_to(inner_residual);
outer_residual->compute_norm2(res_vec);
auto res = exec->copy_val_to_host(res_vec->get_const_values());
if (iter > max_outer_iters || res / initres < outer_reduction_factor) {
break;
}
inner_solution->copy_from(inner_residual);
inner_solver->apply(inner_residual, inner_solution);
inner_solution->convert_to(outer_delta);
x->add_scaled(one, outer_delta);
outer_residual->copy_from(b);
A->apply(neg_one, x, one, outer_residual);
}
auto toc = std::chrono::steady_clock::now();
time += std::chrono::duration_cast<std::chrono::nanoseconds>(toc - tic);
A->apply(one, x, neg_one, b);
b->compute_norm2(res_vec);
std::cout << "Initial residual norm sqrt(r^T r):\n";
write(std::cout, initres_vec);
std::cout << "Final residual norm sqrt(r^T r):\n";
write(std::cout, res_vec);
std::cout << "MPIR iteration count: " << iter << std::endl;
std::cout << "MPIR execution time [ms]: "
<< static_cast<double>(time.count()) / 1000000.0 << std::endl;
}